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[size=1em]想上岸 找上岸 No.1 Check if the Sentence Is Pangram 解题思路 简单遍历字符串判断 非英文字母字符直接返回false 否则记录不同字符的个数是否满足26个 代码展示 - public boolean checkIfPangram(String sentence) {
$ B9 j4 k1 F9 l4 N- F& s8 |- l - if (sentence == null || sentence.length() == 0) {
/ D: x6 _( s% ~6 u( h( T - return false;
! g o1 Z0 J! x( k" a' ] - }
e0 ?& C, C" w - Set<Character> set = new HashSet<>();
% ]. x6 T, E6 `6 a/ x, P - for (char c : sentence.toCharArray()) {
5 x! J" q7 Y; E5 ?' m - if (c - 'a' < 0 || c - 'a' >= 26) {
& m. ^8 H6 i( f- C3 Y - return false;
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; t) I8 M1 ]" J - set.add(c); 9 [ ?8 m2 p+ f, _7 {& v7 S' B* A3 X
- }
% p) a B. s! g9 X8 D6 @ - return set.size() == 26;
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复制代码No.2 Maximum Ice Cream Bars 解题思路 贪心的去买雪糕 无需看成背包问题,TLE or MLE 代码展示 - public int maxIceCream(int[] costs, int coins) { ; m) C7 w% K: c- Q- ]: {
- if (costs == null || costs.length == 0) { ! v& w9 [: e1 Z1 o4 h8 H4 I( ]
- return 0;
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- int n = costs.length; # x, g" I" p9 V, T% Z3 }6 z' r
- int res = 0; ) h4 I; W: D3 q) q, h
- // 排序从小到大买即可 C" e; y- ]' C. r2 A
- Arrays.sort(costs);
/ k, i7 o. e. h" Z8 c/ | - for (int cost : costs) {
$ f1 U7 `. _! w+ w* U5 u - if (coins > cost) { " U( W, D3 |4 F9 ~
- res += 1; & L. E8 {" t1 p8 ]" \- G- q
- coins -= cost; 6 H* F" E8 ~5 a) w8 e. {9 |. u- V2 d
- }
" \" o, i5 T$ ]6 n+ s: _' M - else {
! w0 T) o9 S, J. e - return res; . {2 V/ k/ @, p! x/ N
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- return res;
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