[size=1em]想上岸 找上岸 No.1 Check if the Sentence Is Pangram 解题思路 简单遍历字符串判断 非英文字母字符直接返回false 否则记录不同字符的个数是否满足26个 代码展示 - public boolean checkIfPangram(String sentence) { + Z; Y: m4 k* }5 @; N9 Y- M% n
- if (sentence == null || sentence.length() == 0) { 5 i4 M) M9 j8 G( Q1 U! E2 m
- return false;
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1 K5 S' L+ h9 ~9 ` - Set<Character> set = new HashSet<>(); 0 v. L& E5 V/ o6 ?
- for (char c : sentence.toCharArray()) { ! r- @1 S( `7 l# q9 \3 |# p
- if (c - 'a' < 0 || c - 'a' >= 26) { P- H1 b6 {1 H5 L- h- e
- return false;
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- set.add(c);
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- return set.size() == 26;
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复制代码No.2 Maximum Ice Cream Bars 解题思路 贪心的去买雪糕 无需看成背包问题,TLE or MLE 代码展示 - public int maxIceCream(int[] costs, int coins) {
+ N. A; e$ r( i9 N4 j - if (costs == null || costs.length == 0) {
: {3 f3 Z# J) \% j$ G/ Y+ L - return 0;
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( }. n/ O) o( f g9 T$ m; p0 q" ^ - int n = costs.length; 8 Q& [/ K- q$ v* _% R. T5 S0 z* e
- int res = 0; 0 j) k3 x( s4 A/ k/ ~7 V
- // 排序从小到大买即可 1 _% b& y% @. d' D, H: Z f
- Arrays.sort(costs); ; B$ E I" q8 A; z* ?
- for (int cost : costs) {
8 f H Z0 @. L9 l - if (coins > cost) {
& w7 f0 h- O% D. p0 I - res += 1; " o! ]' f1 ^" o x8 o" {" `
- coins -= cost; 3 ]& e4 R3 [, j# Q: M
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- else {
' ]( Z+ v, {+ N; [. R; m, E* o - return res;
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- }
$ I) y1 o1 H1 u* }/ A: Y; ]3 F W - return res; & }% J4 R- C g' G, x1 A) ?
- }
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